What is the molar mass of (NH4)2SO4?

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Multiple Choice

What is the molar mass of (NH4)2SO4?

Explanation:
To determine the molar mass of ammonium sulfate \((NH_4)_2SO_4\), we need to sum the atomic masses of all the atoms in the formula. Ammonium sulfate consists of two ammonium ions \((NH_4)^+\) and one sulfate ion \((SO_4)^{2-}\). 1. **Calculate the mass of ammonium ions**: - Each ammonium ion contains: - Nitrogen (N): 1 atom × 14.01 g/mol = 14.01 g/mol - Hydrogen (H): 4 atoms × 1.008 g/mol = 4.032 g/mol - Total for one ammonium ion: 14.01 g/mol + 4.032 g/mol = 18.042 g/mol - Since there are two ammonium ions in the formula, the total mass from ammonium is: - 2 × 18.042 g/mol = 36.084 g/mol 2. **Calculate the mass of sulfate ions**: - The sulfate ion contains: - Sulfur (S): 1 atom × 32.07 g/mol = 32.07

To determine the molar mass of ammonium sulfate ((NH_4)_2SO_4), we need to sum the atomic masses of all the atoms in the formula.

Ammonium sulfate consists of two ammonium ions ((NH_4)^+) and one sulfate ion ((SO_4)^{2-}).

  1. Calculate the mass of ammonium ions:
  • Each ammonium ion contains:

  • Nitrogen (N): 1 atom × 14.01 g/mol = 14.01 g/mol

  • Hydrogen (H): 4 atoms × 1.008 g/mol = 4.032 g/mol

  • Total for one ammonium ion: 14.01 g/mol + 4.032 g/mol = 18.042 g/mol

  • Since there are two ammonium ions in the formula, the total mass from ammonium is:

  • 2 × 18.042 g/mol = 36.084 g/mol

  1. Calculate the mass of sulfate ions:
  • The sulfate ion contains:

  • Sulfur (S): 1 atom × 32.07 g/mol = 32.07

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